8075543320121 has 2 divisors, whose sum is σ = 8075543320122. Its totient is φ = 8075543320120.

The previous prime is 8075543320099. The next prime is 8075543320123. The reversal of 8075543320121 is 1210233455708.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4380167623225 + 3695375696896 = 2092885^2 + 1922336^2 .

It is a cyclic number.

It is not a de Polignac number, because 8075543320121 - 2⁶ = 8075543320057 is a prime.

It is a Sophie Germain prime.

Together with 8075543320123, it forms a pair of twin primes.

It is a Chen prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (8075543320123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4037771660060 + 4037771660061.

It is an arithmetic number, because the mean of its divisors is an integer number (4037771660061).

Almost surely, 2^{8075543320121} is an apocalyptic number.

It is an amenable number.

8075543320121 is a deficient number, since it is larger than the sum of its proper divisors (1).

8075543320121 is an equidigital number, since it uses as much as digits as its factorization.

8075543320121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 201600, while the sum is 41.

Adding to 8075543320121 its reverse (1210233455708), we get a palindrome (9285776775829).

The spelling of 8075543320121 in words is "eight trillion, seventy-five billion, five hundred forty-three million, three hundred twenty thousand, one hundred twenty-one".