Base | Representation |
---|---|
bin | 111010111000101101101… |
… | …1100100010010110011011 |
3 | 1001122201002200120221211221 |
4 | 1311301123130202112123 |
5 | 2030044440130434201 |
6 | 25113553334432511 |
7 | 1463501225660323 |
oct | 165613334422633 |
9 | 31581080527757 |
10 | 8093252593051 |
11 | 264036910965a |
12 | aa8639b02737 |
13 | 46926253a6c2 |
14 | 1dda03536283 |
15 | e07cdb2d4a1 |
hex | 75c5b72259b |
8093252593051 has 2 divisors, whose sum is σ = 8093252593052. Its totient is φ = 8093252593050.
The previous prime is 8093252593033. The next prime is 8093252593081. The reversal of 8093252593051 is 1503952523908.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 8093252593051 - 29 = 8093252592539 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 8093252593051.
It is not a weakly prime, because it can be changed into another prime (8093252593081) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4046626296525 + 4046626296526.
It is an arithmetic number, because the mean of its divisors is an integer number (4046626296526).
Almost surely, 28093252593051 is an apocalyptic number.
8093252593051 is a deficient number, since it is larger than the sum of its proper divisors (1).
8093252593051 is an equidigital number, since it uses as much as digits as its factorization.
8093252593051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2916000, while the sum is 52.
The spelling of 8093252593051 in words is "eight trillion, ninety-three billion, two hundred fifty-two million, five hundred ninety-three thousand, fifty-one".
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