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8093252593081 is a prime number
BaseRepresentation
bin111010111000101101101…
…1100100010010110111001
31001122201002200120221220001
41311301123130202112321
52030044440130434311
625113553334433001
71463501225660365
oct165613334422671
931581080527801
108093252593081
112640369109687
12aa8639b02761
1346926253a716
141dda035362a5
15e07cdb2d4c1
hex75c5b7225b9

8093252593081 has 2 divisors, whose sum is σ = 8093252593082. Its totient is φ = 8093252593080.

The previous prime is 8093252593051. The next prime is 8093252593103. The reversal of 8093252593081 is 1803952523908.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 6049710867456 + 2043541725625 = 2459616^2 + 1429525^2 .

It is a cyclic number.

It is not a de Polignac number, because 8093252593081 - 215 = 8093252560313 is a prime.

It is a super-2 number, since 2×80932525930812 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (8093252593051) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4046626296540 + 4046626296541.

It is an arithmetic number, because the mean of its divisors is an integer number (4046626296541).

Almost surely, 28093252593081 is an apocalyptic number.

It is an amenable number.

8093252593081 is a deficient number, since it is larger than the sum of its proper divisors (1).

8093252593081 is an equidigital number, since it uses as much as digits as its factorization.

8093252593081 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4665600, while the sum is 55.

The spelling of 8093252593081 in words is "eight trillion, ninety-three billion, two hundred fifty-two million, five hundred ninety-three thousand, eighty-one".