Base | Representation |
---|---|
bin | 110000010101110… |
… | …010111010011101 |
3 | 2002112002002012022 |
4 | 300111302322131 |
5 | 3130110114213 |
6 | 212250545525 |
7 | 26045361413 |
oct | 6025627235 |
9 | 2075062168 |
10 | 811019933 |
11 | 386888309 |
12 | 1a77382a5 |
13 | cc040a69 |
14 | 799d72b3 |
15 | 4b302308 |
hex | 30572e9d |
811019933 has 2 divisors, whose sum is σ = 811019934. Its totient is φ = 811019932.
The previous prime is 811019929. The next prime is 811020011. The reversal of 811019933 is 339910118.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 563492644 + 247527289 = 23738^2 + 15733^2 .
It is a cyclic number.
It is not a de Polignac number, because 811019933 - 22 = 811019929 is a prime.
It is a super-4 number, since 4×8110199334 (a number of 37 digits) contains 4444 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 811019893 and 811019902.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (811019903) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 405509966 + 405509967.
It is an arithmetic number, because the mean of its divisors is an integer number (405509967).
Almost surely, 2811019933 is an apocalyptic number.
It is an amenable number.
811019933 is a deficient number, since it is larger than the sum of its proper divisors (1).
811019933 is an equidigital number, since it uses as much as digits as its factorization.
811019933 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5832, while the sum is 35.
The square root of 811019933 is about 28478.4117007954. The cubic root of 811019933 is about 932.5608431096.
The spelling of 811019933 in words is "eight hundred eleven million, nineteen thousand, nine hundred thirty-three".
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