81115108141 has 2 divisors, whose sum is σ = 81115108142. Its totient is φ = 81115108140.

The previous prime is 81115108127. The next prime is 81115108147. The reversal of 81115108141 is 14180151118.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 41798166916 + 39316941225 = 204446^2 + 198285^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-81115108141 is a prime.

It is a super-3 number, since 3×81115108141³ (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (81115108147) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 40557554070 + 40557554071.

It is an arithmetic number, because the mean of its divisors is an integer number (40557554071).

Almost surely, 2^81115108141 is an apocalyptic number.

It is an amenable number.

81115108141 is a deficient number, since it is larger than the sum of its proper divisors (1).

81115108141 is an equidigital number, since it uses as much as digits as its factorization.

81115108141 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1280, while the sum is 31.

Adding to 81115108141 its reverse (14180151118), we get a palindrome (95295259259).

The spelling of 81115108141 in words is "eighty-one billion, one hundred fifteen million, one hundred eight thousand, one hundred forty-one".