8112119 has 2 divisors, whose sum is σ = 8112120. Its totient is φ = 8112118.

The previous prime is 8112109. The next prime is 8112133. The reversal of 8112119 is 9112118.

8112119 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 8112119 - 2⁴ = 8112103 is a prime.

It is a super-2 number, since 2×8112119² = 131612949340322, which contains 22 as substring.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 8112094 and 8112103.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (8112109) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4056059 + 4056060.

It is an arithmetic number, because the mean of its divisors is an integer number (4056060).

Almost surely, 2^8112119 is an apocalyptic number.

8112119 is a deficient number, since it is larger than the sum of its proper divisors (1).

8112119 is an equidigital number, since it uses as much as digits as its factorization.

8112119 is an evil number, because the sum of its binary digits is even.

The product of its digits is 144, while the sum is 23.

The square root of 8112119 is about 2848.1781896504. The cubic root of 8112119 is about 200.9299938543.

Subtracting 8112119 from its reverse (9112118), we obtain a palindrome (999999).

The spelling of 8112119 in words is "eight million, one hundred twelve thousand, one hundred nineteen".