Base | Representation |
---|---|
bin | 10010011101011000100100… |
… | …001000100010001010000111 |
3 | 101122110010021222121001120011 |
4 | 102131120210020202022013 |
5 | 41120104442434431311 |
6 | 444355241154251051 |
7 | 23046233064340045 |
oct | 2235304410421207 |
9 | 348403258531504 |
10 | 81184078045831 |
11 | 2395aa79657422 |
12 | 9132027586a87 |
13 | 363b8198bb767 |
14 | 160948a665395 |
15 | 95bbb68e8321 |
hex | 49d624222287 |
81184078045831 has 2 divisors, whose sum is σ = 81184078045832. Its totient is φ = 81184078045830.
The previous prime is 81184078045723. The next prime is 81184078045877. The reversal of 81184078045831 is 13854087048118.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 81184078045831 - 227 = 81183943828103 is a prime.
It is a super-2 number, since 2×811840780458312 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (81184078055831) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 40592039022915 + 40592039022916.
It is an arithmetic number, because the mean of its divisors is an integer number (40592039022916).
Almost surely, 281184078045831 is an apocalyptic number.
81184078045831 is a deficient number, since it is larger than the sum of its proper divisors (1).
81184078045831 is an equidigital number, since it uses as much as digits as its factorization.
81184078045831 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6881280, while the sum is 58.
The spelling of 81184078045831 in words is "eighty-one trillion, one hundred eighty-four billion, seventy-eight million, forty-five thousand, eight hundred thirty-one".
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