812018131 has 2 divisors, whose sum is σ = 812018132. Its totient is φ = 812018130.

The previous prime is 812018117. The next prime is 812018147. The reversal of 812018131 is 131810218.

812018131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 812018131 - 2²⁹ = 275147219 is a prime.

It is a super-2 number, since 2×812018131² = 1318746890145466322, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 812018096 and 812018105.

It is not a weakly prime, because it can be changed into another prime (812018191) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 406009065 + 406009066.

It is an arithmetic number, because the mean of its divisors is an integer number (406009066).

Almost surely, 2^812018131 is an apocalyptic number.

812018131 is a deficient number, since it is larger than the sum of its proper divisors (1).

812018131 is an equidigital number, since it uses as much as digits as its factorization.

812018131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 384, while the sum is 25.

The square root of 812018131 is about 28495.9318324564. The cubic root of 812018131 is about 932.9432828354.

Adding to 812018131 its reverse (131810218), we get a palindrome (943828349).

The spelling of 812018131 in words is "eight hundred twelve million, eighteen thousand, one hundred thirty-one".