Base | Representation |
---|---|
bin | 10111101000101010100… |
… | …00100101011111110101 |
3 | 2212122012000202021011212 |
4 | 23310111100211133311 |
5 | 101301143001111443 |
6 | 1421024235011205 |
7 | 112446505520024 |
oct | 13642520453765 |
9 | 2778160667155 |
10 | 812105488373 |
11 | 293459416343 |
12 | 111484599b05 |
13 | 5b772c26b4a |
14 | 2b43dda28bb |
15 | 161d0e4d618 |
hex | bd154257f5 |
812105488373 has 2 divisors, whose sum is σ = 812105488374. Its totient is φ = 812105488372.
The previous prime is 812105488367. The next prime is 812105488393. The reversal of 812105488373 is 373884501218.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 600659100484 + 211446387889 = 775022^2 + 459833^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-812105488373 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (812105488393) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 406052744186 + 406052744187.
It is an arithmetic number, because the mean of its divisors is an integer number (406052744187).
Almost surely, 2812105488373 is an apocalyptic number.
It is an amenable number.
812105488373 is a deficient number, since it is larger than the sum of its proper divisors (1).
812105488373 is an equidigital number, since it uses as much as digits as its factorization.
812105488373 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1290240, while the sum is 50.
The spelling of 812105488373 in words is "eight hundred twelve billion, one hundred five million, four hundred eighty-eight thousand, three hundred seventy-three".
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