Base | Representation |
---|---|
bin | 10111101000110101111… |
… | …01011100111110000000 |
3 | 2212122102200201200001120 |
4 | 23310122331130332000 |
5 | 101301341442323000 |
6 | 1421041533032240 |
7 | 112452046514052 |
oct | 13643275347600 |
9 | 2778380650046 |
10 | 812201136000 |
11 | 2934a8404871 |
12 | 1114b0625680 |
13 | 5b7899a5587 |
14 | 2b44c97d8d2 |
15 | 161d95436a0 |
hex | bd1af5cf80 |
812201136000 has 256 divisors, whose sum is σ = 2697509805120. Its totient is φ = 216179712000.
The previous prime is 812201135957. The next prime is 812201136011. The reversal of 812201136000 is 631102218.
It is a Harshad number since it is a multiple of its sum of digits (24).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 25952362 + ... + 25983638.
Almost surely, 2812201136000 is an apocalyptic number.
812201136000 is a gapful number since it is divisible by the number (80) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 812201136000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1348754902560).
812201136000 is an abundant number, since it is smaller than the sum of its proper divisors (1885308669120).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
812201136000 is a wasteful number, since it uses less digits than its factorization.
812201136000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 31850 (or 31828 counting only the distinct ones).
The product of its (nonzero) digits is 576, while the sum is 24.
Adding to 812201136000 its reverse (631102218), we get a palindrome (812832238218).
The spelling of 812201136000 in words is "eight hundred twelve billion, two hundred one million, one hundred thirty-six thousand".
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