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81263054407699 is a prime number
BaseRepresentation
bin10010011110100010000111…
…011111011100100000010011
3101122201200010222112221000201
4102132202013133130200103
541122403213412021244
6444455422024000031
723055030146336653
oct2236420737344023
9348650128487021
1081263054407699
1123990516764a7a
1291453a8600017
1336460c492b028
14160d21d49c363
1595dc8a0b6ad4
hex49e8877dc813

81263054407699 has 2 divisors, whose sum is σ = 81263054407700. Its totient is φ = 81263054407698.

The previous prime is 81263054407627. The next prime is 81263054407741. The reversal of 81263054407699 is 99670445036218.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 81263054407699 - 221 = 81263052310547 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 81263054407699.

It is not a weakly prime, because it can be changed into another prime (81263054401699) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 40631527203849 + 40631527203850.

It is an arithmetic number, because the mean of its divisors is an integer number (40631527203850).

It is a 1-persistent number, because it is pandigital, but 2⋅81263054407699 = 162526108815398 is not.

Almost surely, 281263054407699 is an apocalyptic number.

81263054407699 is a deficient number, since it is larger than the sum of its proper divisors (1).

81263054407699 is an equidigital number, since it uses as much as digits as its factorization.

81263054407699 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 78382080, while the sum is 64.

The spelling of 81263054407699 in words is "eighty-one trillion, two hundred sixty-three billion, fifty-four million, four hundred seven thousand, six hundred ninety-nine".