Base | Representation |
---|---|
bin | 100101110111000011… |
… | …0010010101101101101 |
3 | 21202212012220002012001 |
4 | 1023232012102231231 |
5 | 2313002313211003 |
6 | 101203415412301 |
7 | 5605534631254 |
oct | 1135606225555 |
9 | 252765802161 |
10 | 81304038253 |
11 | 31532012349 |
12 | 13910684091 |
13 | 7889354b99 |
14 | 3d1402b79b |
15 | 21acc0a61d |
hex | 12ee192b6d |
81304038253 has 2 divisors, whose sum is σ = 81304038254. Its totient is φ = 81304038252.
The previous prime is 81304038227. The next prime is 81304038259. The reversal of 81304038253 is 35283040318.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 75824781769 + 5479256484 = 275363^2 + 74022^2 .
It is a cyclic number.
It is not a de Polignac number, because 81304038253 - 213 = 81304030061 is a prime.
It is a super-2 number, since 2×813040382532 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (81304038259) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 40652019126 + 40652019127.
It is an arithmetic number, because the mean of its divisors is an integer number (40652019127).
Almost surely, 281304038253 is an apocalyptic number.
It is an amenable number.
81304038253 is a deficient number, since it is larger than the sum of its proper divisors (1).
81304038253 is an equidigital number, since it uses as much as digits as its factorization.
81304038253 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 69120, while the sum is 37.
The spelling of 81304038253 in words is "eighty-one billion, three hundred four million, thirty-eight thousand, two hundred fifty-three".
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