Base | Representation |
---|---|
bin | 10111101010101001001… |
… | …10111011101100000001 |
3 | 2212201221002122020210101 |
4 | 23311110212323230001 |
5 | 101310332041423131 |
6 | 1421321523002401 |
7 | 112515032412262 |
oct | 13652446735401 |
9 | 2781832566711 |
10 | 813168311041 |
11 | 293954348789 |
12 | 111720509401 |
13 | 5b8b218b9b8 |
14 | 2b5011c4969 |
15 | 162443ddc61 |
hex | bd549bbb01 |
813168311041 has 2 divisors, whose sum is σ = 813168311042. Its totient is φ = 813168311040.
The previous prime is 813168310991. The next prime is 813168311047. The reversal of 813168311041 is 140113861318.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 701347626225 + 111820684816 = 837465^2 + 334396^2 .
It is a cyclic number.
It is not a de Polignac number, because 813168311041 - 29 = 813168310529 is a prime.
It is a super-2 number, since 2×8131683110412 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (813168311047) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 406584155520 + 406584155521.
It is an arithmetic number, because the mean of its divisors is an integer number (406584155521).
Almost surely, 2813168311041 is an apocalyptic number.
It is an amenable number.
813168311041 is a deficient number, since it is larger than the sum of its proper divisors (1).
813168311041 is an equidigital number, since it uses as much as digits as its factorization.
813168311041 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 13824, while the sum is 37.
The spelling of 813168311041 in words is "eight hundred thirteen billion, one hundred sixty-eight million, three hundred eleven thousand, forty-one".
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