8132059136437 has 2 divisors, whose sum is σ = 8132059136438. Its totient is φ = 8132059136436.

The previous prime is 8132059136389. The next prime is 8132059136459. The reversal of 8132059136437 is 7346319502318.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8006602204836 + 125456931601 = 2829594^2 + 354199^2 .

It is a cyclic number.

It is not a de Polignac number, because 8132059136437 - 2¹¹ = 8132059134389 is a prime.

It is a super-2 number, since 2×8132059136437² (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (8132059131437) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4066029568218 + 4066029568219.

It is an arithmetic number, because the mean of its divisors is an integer number (4066029568219).

It is a 1-persistent number, because it is pandigital, but 2⋅8132059136437 = 16264118272874 is not.

Almost surely, 2^{8132059136437} is an apocalyptic number.

It is an amenable number.

8132059136437 is a deficient number, since it is larger than the sum of its proper divisors (1).

8132059136437 is an equidigital number, since it uses as much as digits as its factorization.

8132059136437 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3265920, while the sum is 52.

The spelling of 8132059136437 in words is "eight trillion, one hundred thirty-two billion, fifty-nine million, one hundred thirty-six thousand, four hundred thirty-seven".