Base | Representation |
---|---|
bin | 100101111000100001… |
… | …1001011100011101001 |
3 | 21202222200001202020021 |
4 | 1023301003023203221 |
5 | 2313103002213103 |
6 | 101212345000441 |
7 | 5610005541424 |
oct | 1136103134351 |
9 | 252880052207 |
10 | 81353554153 |
11 | 31557a62383 |
12 | 13925183121 |
13 | 78966a0b31 |
14 | 3d1a83a9bb |
15 | 21b223bbbd |
hex | 12f10cb8e9 |
81353554153 has 2 divisors, whose sum is σ = 81353554154. Its totient is φ = 81353554152.
The previous prime is 81353554151. The next prime is 81353554187. The reversal of 81353554153 is 35145535318.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 80958459024 + 395095129 = 284532^2 + 19877^2 .
It is a cyclic number.
It is not a de Polignac number, because 81353554153 - 21 = 81353554151 is a prime.
Together with 81353554151, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (81353554151) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 40676777076 + 40676777077.
It is an arithmetic number, because the mean of its divisors is an integer number (40676777077).
Almost surely, 281353554153 is an apocalyptic number.
It is an amenable number.
81353554153 is a deficient number, since it is larger than the sum of its proper divisors (1).
81353554153 is an equidigital number, since it uses as much as digits as its factorization.
81353554153 is an evil number, because the sum of its binary digits is even.
The product of its digits is 540000, while the sum is 43.
The spelling of 81353554153 in words is "eighty-one billion, three hundred fifty-three million, five hundred fifty-four thousand, one hundred fifty-three".
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