Base | Representation |
---|---|
bin | 111011010001011011100… |
… | …0001110100010011011111 |
3 | 1001211210002122122120002111 |
4 | 1312202313001310103133 |
5 | 2031432140121401002 |
6 | 25154212143534451 |
7 | 1500360422306302 |
oct | 166426701642337 |
9 | 31753078576074 |
10 | 8146328700127 |
11 | 26609251a4462 |
12 | ab6990bba427 |
13 | 47127068b117 |
14 | 2023da600b39 |
15 | e1d8859c3d7 |
hex | 768b70744df |
8146328700127 has 2 divisors, whose sum is σ = 8146328700128. Its totient is φ = 8146328700126.
The previous prime is 8146328700091. The next prime is 8146328700131. The reversal of 8146328700127 is 7210078236418.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-8146328700127 is a prime.
It is a super-2 number, since 2×81463287001272 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (8146328700137) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4073164350063 + 4073164350064.
It is an arithmetic number, because the mean of its divisors is an integer number (4073164350064).
Almost surely, 28146328700127 is an apocalyptic number.
8146328700127 is a deficient number, since it is larger than the sum of its proper divisors (1).
8146328700127 is an equidigital number, since it uses as much as digits as its factorization.
8146328700127 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 903168, while the sum is 49.
The spelling of 8146328700127 in words is "eight trillion, one hundred forty-six billion, three hundred twenty-eight million, seven hundred thousand, one hundred twenty-seven".
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