Base | Representation |
---|---|
bin | 10010100101010100010011… |
… | …110111111010010110010011 |
3 | 101201101020112002002202010212 |
4 | 102211110103313322112103 |
5 | 41203023014110141403 |
6 | 445453523450314335 |
7 | 23133513255335423 |
oct | 2245242367722623 |
9 | 351336462082125 |
10 | 81729266099603 |
11 | 24050207043501 |
12 | 91bb819a289ab |
13 | 367b0628b1295 |
14 | 1627a090aa483 |
15 | 96ae747144d8 |
hex | 4a5513dfa593 |
81729266099603 has 2 divisors, whose sum is σ = 81729266099604. Its totient is φ = 81729266099602.
The previous prime is 81729266099597. The next prime is 81729266099609. The reversal of 81729266099603 is 30699066292718.
It is a balanced prime because it is at equal distance from previous prime (81729266099597) and next prime (81729266099609).
It is a cyclic number.
It is not a de Polignac number, because 81729266099603 - 218 = 81729265837459 is a prime.
It is a super-3 number, since 3×817292660996033 (a number of 43 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (81729266099609) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 40864633049801 + 40864633049802.
It is an arithmetic number, because the mean of its divisors is an integer number (40864633049802).
Almost surely, 281729266099603 is an apocalyptic number.
81729266099603 is a deficient number, since it is larger than the sum of its proper divisors (1).
81729266099603 is an equidigital number, since it uses as much as digits as its factorization.
81729266099603 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 105815808, while the sum is 68.
The spelling of 81729266099603 in words is "eighty-one trillion, seven hundred twenty-nine billion, two hundred sixty-six million, ninety-nine thousand, six hundred three".
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