Base | Representation |
---|---|
bin | 11000001010000111000… |
… | …00100011001000111111 |
3 | 2221100112101202201010012 |
4 | 30011003200203020333 |
5 | 102044431142403033 |
6 | 1433154102133435 |
7 | 113653456405004 |
oct | 14050340431077 |
9 | 2840471681105 |
10 | 830061294143 |
11 | 2a0032a62a44 |
12 | 114a55a2127b |
13 | 60374c527a3 |
14 | 2c2649a78ab |
15 | 168d24c7248 |
hex | c14382323f |
830061294143 has 2 divisors, whose sum is σ = 830061294144. Its totient is φ = 830061294142.
The previous prime is 830061294061. The next prime is 830061294151. The reversal of 830061294143 is 341492160038.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 830061294143 - 234 = 812881424959 is a prime.
It is a super-2 number, since 2×8300612941432 (a number of 25 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 830061294143.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (830061294943) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 415030647071 + 415030647072.
It is an arithmetic number, because the mean of its divisors is an integer number (415030647072).
Almost surely, 2830061294143 is an apocalyptic number.
830061294143 is a deficient number, since it is larger than the sum of its proper divisors (1).
830061294143 is an equidigital number, since it uses as much as digits as its factorization.
830061294143 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 124416, while the sum is 41.
The spelling of 830061294143 in words is "eight hundred thirty billion, sixty-one million, two hundred ninety-four thousand, one hundred forty-three".
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