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83080202411441 is a prime number
BaseRepresentation
bin10010111000111110011101…
…111100111101110110110001
3101220011101112011002221101002
4102320332131330331312301
541342141223304131231
6452410303524051345
723333226602456024
oct2270763574756661
9356141464087332
1083080202411441
1124521130401684
1293995bb833b55
1337485777169c1
1416731634751bb
159911902d00cb
hex4b8f9df3ddb1

83080202411441 has 2 divisors, whose sum is σ = 83080202411442. Its totient is φ = 83080202411440.

The previous prime is 83080202411387. The next prime is 83080202411449. The reversal of 83080202411441 is 14411420208038.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 57521667164416 + 25558535247025 = 7584304^2 + 5055545^2 .

It is a cyclic number.

It is not a de Polignac number, because 83080202411441 - 234 = 83063022542257 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 83080202411395 and 83080202411404.

It is not a weakly prime, because it can be changed into another prime (83080202411449) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 41540101205720 + 41540101205721.

It is an arithmetic number, because the mean of its divisors is an integer number (41540101205721).

Almost surely, 283080202411441 is an apocalyptic number.

It is an amenable number.

83080202411441 is a deficient number, since it is larger than the sum of its proper divisors (1).

83080202411441 is an equidigital number, since it uses as much as digits as its factorization.

83080202411441 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 49152, while the sum is 38.

Adding to 83080202411441 its reverse (14411420208038), we get a palindrome (97491622619479).

The spelling of 83080202411441 in words is "eighty-three trillion, eighty billion, two hundred two million, four hundred eleven thousand, four hundred forty-one".