Base | Representation |
---|---|
bin | 100110101100101001… |
… | …0110010001011111000 |
3 | 21221111112222010121110 |
4 | 1031121102302023320 |
5 | 2330143213200000 |
6 | 102102102240320 |
7 | 6001233245136 |
oct | 1153122621370 |
9 | 257445863543 |
10 | 83102475000 |
11 | 322751a9506 |
12 | 14132a260a0 |
13 | 7ab4b1853c |
14 | 4044c18756 |
15 | 2265a55850 |
hex | 13594b22f8 |
83102475000 has 288 divisors, whose sum is σ = 268558279920. Its totient is φ = 21427200000.
The previous prime is 83102474999. The next prime is 83102475041. The reversal of 83102475000 is 57420138.
It is a super-2 number, since 2×831024750002 (a number of 23 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (30).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 72074424 + ... + 72075576.
Almost surely, 283102475000 is an apocalyptic number.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 83102475000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (134279139960).
83102475000 is an abundant number, since it is smaller than the sum of its proper divisors (185455804920).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
83102475000 is a wasteful number, since it uses less digits than its factorization.
83102475000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1249 (or 1194 counting only the distinct ones).
The product of its (nonzero) digits is 6720, while the sum is 30.
Adding to 83102475000 its reverse (57420138), we get a palindrome (83159895138).
The spelling of 83102475000 in words is "eighty-three billion, one hundred two million, four hundred seventy-five thousand".
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