Base | Representation |
---|---|
bin | 10010111001100110111101… |
… | …110100101001011000100011 |
3 | 101220022112202122121110011002 |
4 | 102321212331310221120203 |
5 | 41343344302303234212 |
6 | 452442254452542215 |
7 | 23336326306451114 |
oct | 2271467564513043 |
9 | 356275678543132 |
10 | 83123686774307 |
11 | 24538615177053 |
12 | 93a5b1662196b |
13 | 374c6b761c22a |
14 | 16752ca6d020b |
15 | 992387b35ac2 |
hex | 4b99bdd29623 |
83123686774307 has 2 divisors, whose sum is σ = 83123686774308. Its totient is φ = 83123686774306.
The previous prime is 83123686774199. The next prime is 83123686774309. The reversal of 83123686774307 is 70347768632138.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-83123686774307 is a prime.
Together with 83123686774309, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (83123686774309) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 41561843387153 + 41561843387154.
It is an arithmetic number, because the mean of its divisors is an integer number (41561843387154).
Almost surely, 283123686774307 is an apocalyptic number.
83123686774307 is a deficient number, since it is larger than the sum of its proper divisors (1).
83123686774307 is an equidigital number, since it uses as much as digits as its factorization.
83123686774307 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 170698752, while the sum is 65.
The spelling of 83123686774307 in words is "eighty-three trillion, one hundred twenty-three billion, six hundred eighty-six million, seven hundred seventy-four thousand, three hundred seven".
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