Base | Representation |
---|---|
bin | 100110101101100101… |
… | …1001101010000100101 |
3 | 21221120202100222000001 |
4 | 1031123023031100211 |
5 | 2330224303340143 |
6 | 102105151021301 |
7 | 6002065464466 |
oct | 1153313152045 |
9 | 257522328001 |
10 | 83134043173 |
11 | 32291000105 |
12 | 1414150a831 |
13 | 7abb51c22c |
14 | 40490b4d6d |
15 | 22686de14d |
hex | 135b2cd425 |
83134043173 has 2 divisors, whose sum is σ = 83134043174. Its totient is φ = 83134043172.
The previous prime is 83134043129. The next prime is 83134043269. The reversal of 83134043173 is 37134043138.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 82963009089 + 171034084 = 288033^2 + 13078^2 .
It is a cyclic number.
It is not a de Polignac number, because 83134043173 - 29 = 83134042661 is a prime.
It is a super-2 number, since 2×831340431732 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (83134043873) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 41567021586 + 41567021587.
It is an arithmetic number, because the mean of its divisors is an integer number (41567021587).
Almost surely, 283134043173 is an apocalyptic number.
It is an amenable number.
83134043173 is a deficient number, since it is larger than the sum of its proper divisors (1).
83134043173 is an equidigital number, since it uses as much as digits as its factorization.
83134043173 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72576, while the sum is 37.
The spelling of 83134043173 in words is "eighty-three billion, one hundred thirty-four million, forty-three thousand, one hundred seventy-three".
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