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83261041 is a prime number
BaseRepresentation
bin1001111011001…
…11011001110001
312210200002200021
410331213121301
5132303323131
612132323441
72030464363
oct475473161
9183602607
1083261041
1142aa9286
1223a73581
13143327b6
14b0b4d33
157499e11
hex4f67671

83261041 has 2 divisors, whose sum is σ = 83261042. Its totient is φ = 83261040.

The previous prime is 83261027. The next prime is 83261089. The reversal of 83261041 is 14016238.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 82882816 + 378225 = 9104^2 + 615^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-83261041 is a prime.

It is a super-3 number, since 3×832610413 (a number of 25 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 83260997 and 83261015.

It is not a weakly prime, because it can be changed into another prime (83261341) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 41630520 + 41630521.

It is an arithmetic number, because the mean of its divisors is an integer number (41630521).

Almost surely, 283261041 is an apocalyptic number.

It is an amenable number.

83261041 is a deficient number, since it is larger than the sum of its proper divisors (1).

83261041 is an equidigital number, since it uses as much as digits as its factorization.

83261041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1152, while the sum is 25.

The square root of 83261041 is about 9124.7488184607. The cubic root of 83261041 is about 436.6638894863.

Adding to 83261041 its reverse (14016238), we get a palindrome (97277279).

It can be divided in two parts, 8326 and 1041, that multiplied together give a triangular number (8667366 = T4163).

The spelling of 83261041 in words is "eighty-three million, two hundred sixty-one thousand, forty-one".