Base | Representation |
---|---|
bin | 110001101001001… |
… | …110011000100111 |
3 | 2011001020012211212 |
4 | 301221032120213 |
5 | 3201204443112 |
6 | 214351422035 |
7 | 26432310626 |
oct | 6151163047 |
9 | 2131205755 |
10 | 832890407 |
11 | 398165988 |
12 | 1b2b2491b |
13 | 10372a67b |
14 | 7c88b6bd |
15 | 4d1c2522 |
hex | 31a4e627 |
832890407 has 2 divisors, whose sum is σ = 832890408. Its totient is φ = 832890406.
The previous prime is 832890371. The next prime is 832890419. The reversal of 832890407 is 704098238.
832890407 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 832890407 - 212 = 832886311 is a prime.
It is a super-4 number, since 4×8328904074 (a number of 37 digits) contains 4444 as substring. Note that it is a super-d number also for d = 3.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (832890437) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 416445203 + 416445204.
It is an arithmetic number, because the mean of its divisors is an integer number (416445204).
Almost surely, 2832890407 is an apocalyptic number.
832890407 is a deficient number, since it is larger than the sum of its proper divisors (1).
832890407 is an equidigital number, since it uses as much as digits as its factorization.
832890407 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 96768, while the sum is 41.
The square root of 832890407 is about 28859.8407306763. The cubic root of 832890407 is about 940.8692754786.
The spelling of 832890407 in words is "eight hundred thirty-two million, eight hundred ninety thousand, four hundred seven".
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