Base | Representation |
---|---|
bin | 100110110101101010… |
… | …1101000101000010101 |
3 | 21222021122121202221122 |
4 | 1031223111220220111 |
5 | 2331303213242211 |
6 | 102152115053325 |
7 | 6011600414624 |
oct | 1155325505025 |
9 | 258248552848 |
10 | 83405212181 |
11 | 32410082425 |
12 | 141b82a1245 |
13 | 7b32764175 |
14 | 40731016bb |
15 | 22824056db |
hex | 136b568a15 |
83405212181 has 2 divisors, whose sum is σ = 83405212182. Its totient is φ = 83405212180.
The previous prime is 83405212157. The next prime is 83405212213. The reversal of 83405212181 is 18121250438.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 70751212081 + 12654000100 = 265991^2 + 112490^2 .
It is a cyclic number.
It is not a de Polignac number, because 83405212181 - 210 = 83405211157 is a prime.
It is a super-2 number, since 2×834052121812 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (83405212981) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 41702606090 + 41702606091.
It is an arithmetic number, because the mean of its divisors is an integer number (41702606091).
Almost surely, 283405212181 is an apocalyptic number.
It is an amenable number.
83405212181 is a deficient number, since it is larger than the sum of its proper divisors (1).
83405212181 is an equidigital number, since it uses as much as digits as its factorization.
83405212181 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15360, while the sum is 35.
The spelling of 83405212181 in words is "eighty-three billion, four hundred five million, two hundred twelve thousand, one hundred eighty-one".
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