Base | Representation |
---|---|
bin | 1111100010010111… |
… | …10001000111011001 |
3 | 210112022202001022111 |
4 | 13301023301013121 |
5 | 114040342023423 |
6 | 3455412152321 |
7 | 413464254031 |
oct | 76113610731 |
9 | 23468661274 |
10 | 8341361113 |
11 | 35a0532078 |
12 | 17496086a1 |
13 | a2c193147 |
14 | 591b668c1 |
15 | 33c47960d |
hex | 1f12f11d9 |
8341361113 has 2 divisors, whose sum is σ = 8341361114. Its totient is φ = 8341361112.
The previous prime is 8341361111. The next prime is 8341361159. The reversal of 8341361113 is 3111631438.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 4287237529 + 4054123584 = 65477^2 + 63672^2 .
It is a cyclic number.
It is not a de Polignac number, because 8341361113 - 21 = 8341361111 is a prime.
It is a super-3 number, since 3×83413611133 (a number of 31 digits) contains 333 as substring.
Together with 8341361111, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (8341361111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4170680556 + 4170680557.
It is an arithmetic number, because the mean of its divisors is an integer number (4170680557).
Almost surely, 28341361113 is an apocalyptic number.
It is an amenable number.
8341361113 is a deficient number, since it is larger than the sum of its proper divisors (1).
8341361113 is an equidigital number, since it uses as much as digits as its factorization.
8341361113 is an evil number, because the sum of its binary digits is even.
The product of its digits is 5184, while the sum is 31.
The square root of 8341361113 is about 91331.0522932918. The cubic root of 8341361113 is about 2028.0514772863.
The spelling of 8341361113 in words is "eight billion, three hundred forty-one million, three hundred sixty-one thousand, one hundred thirteen".
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