Base | Representation |
---|---|
bin | 1001111110000… |
… | …00010010101011 |
3 | 12211100121010002 |
4 | 10333000102223 |
5 | 132402001011 |
6 | 12144213215 |
7 | 2033542022 |
oct | 477002253 |
9 | 184317102 |
10 | 83625131 |
11 | 43227887 |
12 | 2400a20b |
13 | 1442c435 |
14 | b16b8b9 |
15 | 751cc3b |
hex | 4fc04ab |
83625131 has 2 divisors, whose sum is σ = 83625132. Its totient is φ = 83625130.
The previous prime is 83625119. The next prime is 83625133. The reversal of 83625131 is 13152638.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 83625131 - 214 = 83608747 is a prime.
It is a super-2 number, since 2×836251312 = 13986325069534322, which contains 22 as substring.
Together with 83625133, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 83625094 and 83625103.
It is not a weakly prime, because it can be changed into another prime (83625133) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 41812565 + 41812566.
It is an arithmetic number, because the mean of its divisors is an integer number (41812566).
Almost surely, 283625131 is an apocalyptic number.
83625131 is a deficient number, since it is larger than the sum of its proper divisors (1).
83625131 is an equidigital number, since it uses as much as digits as its factorization.
83625131 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 4320, while the sum is 29.
The square root of 83625131 is about 9144.6777417250. The cubic root of 83625131 is about 437.2994559513.
Adding to 83625131 its reverse (13152638), we get a palindrome (96777769).
The spelling of 83625131 in words is "eighty-three million, six hundred twenty-five thousand, one hundred thirty-one".
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