Base | Representation |
---|---|
bin | 10011000010001000001000… |
… | …001100010010111110011111 |
3 | 101222101111200121212101002221 |
4 | 103002020020030102332133 |
5 | 41432442113302241343 |
6 | 454011223503130211 |
7 | 23426531203225036 |
oct | 2302101014227637 |
9 | 358344617771087 |
10 | 83709050040223 |
11 | 247438995036a3 |
12 | 947b45b5a3967 |
13 | 3792963a7cb2a |
14 | 169577aab171d |
15 | 9a26e79e85ed |
hex | 4c2208312f9f |
83709050040223 has 2 divisors, whose sum is σ = 83709050040224. Its totient is φ = 83709050040222.
The previous prime is 83709050040197. The next prime is 83709050040337. The reversal of 83709050040223 is 32204005090738.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 83709050040223 - 217 = 83709049909151 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 83709050040223.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (83709050040823) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 41854525020111 + 41854525020112.
It is an arithmetic number, because the mean of its divisors is an integer number (41854525020112).
Almost surely, 283709050040223 is an apocalyptic number.
83709050040223 is a deficient number, since it is larger than the sum of its proper divisors (1).
83709050040223 is an equidigital number, since it uses as much as digits as its factorization.
83709050040223 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 362880, while the sum is 43.
The spelling of 83709050040223 in words is "eighty-three trillion, seven hundred nine billion, fifty million, forty thousand, two hundred twenty-three".
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