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83805442141 is a prime number
BaseRepresentation
bin100111000001100110…
…0011001000001011101
322000022112201120020111
41032003030121001131
52333113143122031
6102255533250021
76024530335051
oct1160314310135
9260275646214
1083805442141
11325a5a95093
12142aa333911
137b97656325
1440b0325c61
1522a76121b1
hex138331905d

83805442141 has 2 divisors, whose sum is σ = 83805442142. Its totient is φ = 83805442140.

The previous prime is 83805442057. The next prime is 83805442159. The reversal of 83805442141 is 14124450838.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 60715424025 + 23090018116 = 246405^2 + 151954^2 .

It is a cyclic number.

It is not a de Polignac number, because 83805442141 - 211 = 83805440093 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 83805442094 and 83805442103.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (83805242141) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 41902721070 + 41902721071.

It is an arithmetic number, because the mean of its divisors is an integer number (41902721071).

Almost surely, 283805442141 is an apocalyptic number.

It is an amenable number.

83805442141 is a deficient number, since it is larger than the sum of its proper divisors (1).

83805442141 is an equidigital number, since it uses as much as digits as its factorization.

83805442141 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 122880, while the sum is 40.

Adding to 83805442141 its reverse (14124450838), we get a palindrome (97929892979).

The spelling of 83805442141 in words is "eighty-three billion, eight hundred five million, four hundred forty-two thousand, one hundred forty-one".