Base | Representation |
---|---|
bin | 100111000010110000… |
… | …1000000101101011011 |
3 | 22000102021000221010122 |
4 | 1032011201000231123 |
5 | 2333203131331021 |
6 | 102303444303455 |
7 | 6025512441506 |
oct | 1160541005533 |
9 | 260367027118 |
10 | 83844402011 |
11 | 32615a85227 |
12 | 142bb3a1b8b |
13 | 7ba27475c6 |
14 | 40b558813d |
15 | 22aac5abab |
hex | 1385840b5b |
83844402011 has 2 divisors, whose sum is σ = 83844402012. Its totient is φ = 83844402010.
The previous prime is 83844402001. The next prime is 83844402013. The reversal of 83844402011 is 11020444838.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-83844402011 is a prime.
Together with 83844402013, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (83844402013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 41922201005 + 41922201006.
It is an arithmetic number, because the mean of its divisors is an integer number (41922201006).
Almost surely, 283844402011 is an apocalyptic number.
83844402011 is a deficient number, since it is larger than the sum of its proper divisors (1).
83844402011 is an equidigital number, since it uses as much as digits as its factorization.
83844402011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24576, while the sum is 35.
Adding to 83844402011 its reverse (11020444838), we get a palindrome (94864846849).
The spelling of 83844402011 in words is "eighty-three billion, eight hundred forty-four million, four hundred two thousand, eleven".
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