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83844893117 is a prime number
BaseRepresentation
bin100111000010110001…
…0111000100110111101
322000102021221212210202
41032011202320212331
52333203243034432
6102303503013245
76025516555346
oct1160542704675
9260367855722
1083844893117
11326162901a7
12142bb59a225
137ba2889cbb
1440b56750cd
1522aad06462
hex13858b89bd

83844893117 has 2 divisors, whose sum is σ = 83844893118. Its totient is φ = 83844893116.

The previous prime is 83844893089. The next prime is 83844893123. The reversal of 83844893117 is 71139844838.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 72842771236 + 11002121881 = 269894^2 + 104891^2 .

It is a cyclic number.

It is not a de Polignac number, because 83844893117 - 212 = 83844889021 is a prime.

It is a super-2 number, since 2×838448931172 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (83844895117) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 41922446558 + 41922446559.

It is an arithmetic number, because the mean of its divisors is an integer number (41922446559).

Almost surely, 283844893117 is an apocalyptic number.

It is an amenable number.

83844893117 is a deficient number, since it is larger than the sum of its proper divisors (1).

83844893117 is an equidigital number, since it uses as much as digits as its factorization.

83844893117 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 4644864, while the sum is 56.

The spelling of 83844893117 in words is "eighty-three billion, eight hundred forty-four million, eight hundred ninety-three thousand, one hundred seventeen".