Base | Representation |
---|---|
bin | 10011000111111101101010… |
… | …001010010000111001110011 |
3 | 102000210211221021100112012102 |
4 | 103013331222022100321303 |
5 | 42011030014130230024 |
6 | 454515354105051015 |
7 | 23500520215426334 |
oct | 2307755212207163 |
9 | 360724837315172 |
10 | 84110125633139 |
11 | 248889a419a961 |
12 | 9525132a86a6b |
13 | 37c17211a4788 |
14 | 16aad47a5c28b |
15 | 9acd6da561ae |
hex | 4c7f6a290e73 |
84110125633139 has 2 divisors, whose sum is σ = 84110125633140. Its totient is φ = 84110125633138.
The previous prime is 84110125633111. The next prime is 84110125633159. The reversal of 84110125633139 is 93133652101148.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 84110125633139 - 216 = 84110125567603 is a prime.
It is a super-2 number, since 2×841101256331392 (a number of 29 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 84110125633093 and 84110125633102.
It is not a weakly prime, because it can be changed into another prime (84110125633159) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 42055062816569 + 42055062816570.
It is an arithmetic number, because the mean of its divisors is an integer number (42055062816570).
Almost surely, 284110125633139 is an apocalyptic number.
84110125633139 is a deficient number, since it is larger than the sum of its proper divisors (1).
84110125633139 is an equidigital number, since it uses as much as digits as its factorization.
84110125633139 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 466560, while the sum is 47.
The spelling of 84110125633139 in words is "eighty-four trillion, one hundred ten billion, one hundred twenty-five million, six hundred thirty-three thousand, one hundred thirty-nine".
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