Base | Representation |
---|---|
bin | 100111001100010011… |
… | …1010001010010111001 |
3 | 22001020120221100010222 |
4 | 1032120213101102321 |
5 | 2334332142404123 |
6 | 102355331545425 |
7 | 6036453036362 |
oct | 1163047212271 |
9 | 261216840128 |
10 | 84164809913 |
11 | 3276a928448 |
12 | 1438a75b275 |
13 | 7c23c3c392 |
14 | 4105d50b69 |
15 | 22c8e4b6c8 |
hex | 13989d14b9 |
84164809913 has 2 divisors, whose sum is σ = 84164809914. Its totient is φ = 84164809912.
The previous prime is 84164809879. The next prime is 84164809919. The reversal of 84164809913 is 31990846148.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 84048967744 + 115842169 = 289912^2 + 10763^2 .
It is a cyclic number.
It is not a de Polignac number, because 84164809913 - 214 = 84164793529 is a prime.
It is not a weakly prime, because it can be changed into another prime (84164809919) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 42082404956 + 42082404957.
It is an arithmetic number, because the mean of its divisors is an integer number (42082404957).
Almost surely, 284164809913 is an apocalyptic number.
It is an amenable number.
84164809913 is a deficient number, since it is larger than the sum of its proper divisors (1).
84164809913 is an equidigital number, since it uses as much as digits as its factorization.
84164809913 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1492992, while the sum is 53.
The spelling of 84164809913 in words is "eighty-four billion, one hundred sixty-four million, eight hundred nine thousand, nine hundred thirteen".
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