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848241264613 is a prime number
BaseRepresentation
bin11000101011111110001…
…11101000011111100101
310000002110101120220012211
430111333013220133211
5102344144230431423
61445402054043421
7115166131533241
oct14257707503745
93002411526184
10848241264613
112a7812097926
1211848a349571
1361cb1546672
142d0ab281421
15170e858010d
hexc57f1e87e5

848241264613 has 2 divisors, whose sum is σ = 848241264614. Its totient is φ = 848241264612.

The previous prime is 848241264583. The next prime is 848241264641. The reversal of 848241264613 is 316462142848.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 785930121729 + 62311142884 = 886527^2 + 249622^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-848241264613 is a prime.

It is a super-2 number, since 2×8482412646132 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (848241264313) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 424120632306 + 424120632307.

It is an arithmetic number, because the mean of its divisors is an integer number (424120632307).

Almost surely, 2848241264613 is an apocalyptic number.

It is an amenable number.

848241264613 is a deficient number, since it is larger than the sum of its proper divisors (1).

848241264613 is an equidigital number, since it uses as much as digits as its factorization.

848241264613 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1769472, while the sum is 49.

The spelling of 848241264613 in words is "eight hundred forty-eight billion, two hundred forty-one million, two hundred sixty-four thousand, six hundred thirteen".