Base | Representation |
---|---|
bin | 100111101111010110… |
… | …0111110101001010011 |
3 | 22011021112121022212212 |
4 | 1033132230332221103 |
5 | 2344234210232012 |
6 | 103112135342335 |
7 | 6110552036042 |
oct | 1173654765123 |
9 | 264245538785 |
10 | 85340711507 |
11 | 33213674747 |
12 | 146585219ab |
13 | 8080746b3c |
14 | 41b81aa559 |
15 | 23472c6b22 |
hex | 13deb3ea53 |
85340711507 has 2 divisors, whose sum is σ = 85340711508. Its totient is φ = 85340711506.
The previous prime is 85340711419. The next prime is 85340711593. The reversal of 85340711507 is 70511704358.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 85340711507 - 214 = 85340695123 is a prime.
It is a super-2 number, since 2×853407115072 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (85340701507) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 42670355753 + 42670355754.
It is an arithmetic number, because the mean of its divisors is an integer number (42670355754).
Almost surely, 285340711507 is an apocalyptic number.
85340711507 is a deficient number, since it is larger than the sum of its proper divisors (1).
85340711507 is an equidigital number, since it uses as much as digits as its factorization.
85340711507 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 117600, while the sum is 41.
The spelling of 85340711507 in words is "eighty-five billion, three hundred forty million, seven hundred eleven thousand, five hundred seven".
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