Base | Representation |
---|---|
bin | 100111110000101010… |
… | …0110010001101100111 |
3 | 22011101121101012211000 |
4 | 1033201110302031213 |
5 | 2344331440411100 |
6 | 103120350244343 |
7 | 6111624660453 |
oct | 1174124621547 |
9 | 264347335730 |
10 | 85384700775 |
11 | 3323648a510 |
12 | 1466b1b66b3 |
13 | 80898a93aa |
14 | 41bdd7b663 |
15 | 234b0b5900 |
hex | 13e1532367 |
85384700775 has 48 divisors (see below), whose sum is σ = 171114405120. Its totient is φ = 41398639200.
The previous prime is 85384700771. The next prime is 85384700809. The reversal of 85384700775 is 57700748358.
It is not a de Polignac number, because 85384700775 - 22 = 85384700771 is a prime.
It is a super-3 number, since 3×853847007753 (a number of 34 digits) contains 333 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (85384700771) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 5742387 + ... + 5757236.
It is an arithmetic number, because the mean of its divisors is an integer number (3564883440).
Almost surely, 285384700775 is an apocalyptic number.
85384700775 is an abundant number, since it is smaller than the sum of its proper divisors (85729704345).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
85384700775 is a wasteful number, since it uses less digits than its factorization.
85384700775 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 11499653 (or 11499642 counting only the distinct ones).
The product of its (nonzero) digits is 6585600, while the sum is 54.
The spelling of 85384700775 in words is "eighty-five billion, three hundred eighty-four million, seven hundred thousand, seven hundred seventy-five".
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