Base | Representation |
---|---|
bin | 10011100011001011010001… |
… | …110000000101100010011111 |
3 | 102021102121212011222110220102 |
4 | 103203023101300011202133 |
5 | 42232144344120000241 |
6 | 502510425151411315 |
7 | 24052601605444664 |
oct | 2343132160054237 |
9 | 367377764873812 |
10 | 85980174375071 |
11 | 25439a94a330a9 |
12 | 978764a523b3b |
13 | 38c8b8499bbb2 |
14 | 17336696cda6b |
15 | 9e181d0ec39b |
hex | 4e32d1c0589f |
85980174375071 has 2 divisors, whose sum is σ = 85980174375072. Its totient is φ = 85980174375070.
The previous prime is 85980174375049. The next prime is 85980174375113. The reversal of 85980174375071 is 17057347108958.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 85980174375071 - 210 = 85980174374047 is a prime.
It is a Sophie Germain prime.
It is a junction number, because it is equal to n+sod(n) for n = 85980174374989 and 85980174375007.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (85980174374071) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 42990087187535 + 42990087187536.
It is an arithmetic number, because the mean of its divisors is an integer number (42990087187536).
Almost surely, 285980174375071 is an apocalyptic number.
85980174375071 is a deficient number, since it is larger than the sum of its proper divisors (1).
85980174375071 is an equidigital number, since it uses as much as digits as its factorization.
85980174375071 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 59270400, while the sum is 65.
The spelling of 85980174375071 in words is "eighty-five trillion, nine hundred eighty billion, one hundred seventy-four million, three hundred seventy-five thousand, seventy-one".
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