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86054055401603 is a prime number
BaseRepresentation
bin10011100100010000000101…
…011001110101100010000011
3102021200200120002011111022102
4103210100011121311202003
542234402201140322403
6503004404242301015
724061125500013542
oct2344200531654203
9367620502144272
1086054055401603
1125468357938913
129799a2905776b
133902b2a1b0343
14173707792a159
159e36e42d1b88
hex4e4405675883

86054055401603 has 2 divisors, whose sum is σ = 86054055401604. Its totient is φ = 86054055401602.

The previous prime is 86054055401581. The next prime is 86054055401621. The reversal of 86054055401603 is 30610455045068.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-86054055401603 is a prime.

It is a super-4 number, since 4×860540554016034 (a number of 57 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is a Sophie Germain prime.

It is not a weakly prime, because it can be changed into another prime (86054055406603) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 43027027700801 + 43027027700802.

It is an arithmetic number, because the mean of its divisors is an integer number (43027027700802).

Almost surely, 286054055401603 is an apocalyptic number.

86054055401603 is a deficient number, since it is larger than the sum of its proper divisors (1).

86054055401603 is an equidigital number, since it uses as much as digits as its factorization.

86054055401603 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1728000, while the sum is 47.

The spelling of 86054055401603 in words is "eighty-six trillion, fifty-four billion, fifty-five million, four hundred one thousand, six hundred three".