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87226472147 is a prime number
BaseRepresentation
bin101000100111100011…
…0100101011011010011
322100010221222220011112
41101033012211123103
52412114434102042
6104023222003535
76205360531343
oct1211706453323
9270127886145
1087226472147
1133aa1084611
1214aa3b765ab
1382c1333339
144316808d23
152407b20982
hex144f1a56d3

87226472147 has 2 divisors, whose sum is σ = 87226472148. Its totient is φ = 87226472146.

The previous prime is 87226472143. The next prime is 87226472149. The reversal of 87226472147 is 74127462278.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 87226472147 - 22 = 87226472143 is a prime.

It is a super-3 number, since 3×872264721473 (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

Together with 87226472149, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 87226472095 and 87226472104.

It is not a weakly prime, because it can be changed into another prime (87226472141) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 43613236073 + 43613236074.

It is an arithmetic number, because the mean of its divisors is an integer number (43613236074).

Almost surely, 287226472147 is an apocalyptic number.

87226472147 is a deficient number, since it is larger than the sum of its proper divisors (1).

87226472147 is an equidigital number, since it uses as much as digits as its factorization.

87226472147 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 2107392, while the sum is 50.

The spelling of 87226472147 in words is "eighty-seven billion, two hundred twenty-six million, four hundred seventy-two thousand, one hundred forty-seven".