Base | Representation |
---|---|
bin | 110100000101111… |
… | …110010110011101 |
3 | 2020220112212000022 |
4 | 310011332112131 |
5 | 3242214400331 |
6 | 222420241525 |
7 | 30441501362 |
oct | 6405762635 |
9 | 2226485008 |
10 | 873981341 |
11 | 409381132 |
12 | 2048402a5 |
13 | 10c0b692c |
14 | 84106469 |
15 | 51adc67b |
hex | 3417e59d |
873981341 has 2 divisors, whose sum is σ = 873981342. Its totient is φ = 873981340.
The previous prime is 873981319. The next prime is 873981371. The reversal of 873981341 is 143189378.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 857611225 + 16370116 = 29285^2 + 4046^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-873981341 is a prime.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 873981292 and 873981301.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (873981371) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 436990670 + 436990671.
It is an arithmetic number, because the mean of its divisors is an integer number (436990671).
Almost surely, 2873981341 is an apocalyptic number.
It is an amenable number.
873981341 is a deficient number, since it is larger than the sum of its proper divisors (1).
873981341 is an equidigital number, since it uses as much as digits as its factorization.
873981341 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 145152, while the sum is 44.
The square root of 873981341 is about 29563.1754214597. The cubic root of 873981341 is about 956.0942806739.
The spelling of 873981341 in words is "eight hundred seventy-three million, nine hundred eighty-one thousand, three hundred forty-one".
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