Base | Representation |
---|---|
bin | 11001011101101000010… |
… | …10110111101011110101 |
3 | 10002122021100210100011001 |
4 | 30232310022313223311 |
5 | 103313244141000433 |
6 | 1505531331043301 |
7 | 120131602504435 |
oct | 14566412675365 |
9 | 3078240710131 |
10 | 874901109493 |
11 | 30805295a984 |
12 | 12168a740531 |
13 | 6466c90a0c8 |
14 | 304b9c5a2c5 |
15 | 17b58d2357d |
hex | cbb42b7af5 |
874901109493 has 2 divisors, whose sum is σ = 874901109494. Its totient is φ = 874901109492.
The previous prime is 874901109403. The next prime is 874901109517. The reversal of 874901109493 is 394901109478.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 692859793924 + 182041315569 = 832382^2 + 426663^2 .
It is a cyclic number.
It is not a de Polignac number, because 874901109493 - 217 = 874900978421 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (874901109403) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 437450554746 + 437450554747.
It is an arithmetic number, because the mean of its divisors is an integer number (437450554747).
Almost surely, 2874901109493 is an apocalyptic number.
It is an amenable number.
874901109493 is a deficient number, since it is larger than the sum of its proper divisors (1).
874901109493 is an equidigital number, since it uses as much as digits as its factorization.
874901109493 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1959552, while the sum is 55.
The spelling of 874901109493 in words is "eight hundred seventy-four billion, nine hundred one million, one hundred nine thousand, four hundred ninety-three".
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