Base | Representation |
---|---|
bin | 101001011100011100… |
… | …0010101010011010111 |
3 | 22111201122022101201012 |
4 | 1102320320111103113 |
5 | 2424233241332413 |
6 | 104515254522435 |
7 | 6300350021555 |
oct | 1227070252327 |
9 | 274648271635 |
10 | 89001120983 |
11 | 348218a3545 |
12 | 152ba36641b |
13 | 8514bb83c8 |
14 | 44443a2bd5 |
15 | 24ad81c7a8 |
hex | 14b8e154d7 |
89001120983 has 2 divisors, whose sum is σ = 89001120984. Its totient is φ = 89001120982.
The previous prime is 89001120977. The next prime is 89001121049. The reversal of 89001120983 is 38902110098.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 89001120983 - 210 = 89001119959 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 89001120983.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (89001120953) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 44500560491 + 44500560492.
It is an arithmetic number, because the mean of its divisors is an integer number (44500560492).
Almost surely, 289001120983 is an apocalyptic number.
89001120983 is a deficient number, since it is larger than the sum of its proper divisors (1).
89001120983 is an equidigital number, since it uses as much as digits as its factorization.
89001120983 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 31104, while the sum is 41.
The spelling of 89001120983 in words is "eighty-nine billion, one million, one hundred twenty thousand, nine hundred eighty-three".
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