Base | Representation |
---|---|
bin | 101001101001010101… |
… | …1101111111101010111 |
3 | 22112211210220110010012 |
4 | 1103102223233331113 |
5 | 2431130102424121 |
6 | 105030241350435 |
7 | 6314154465662 |
oct | 1232253577527 |
9 | 275753813105 |
10 | 89434029911 |
11 | 34a241a6416 |
12 | 153bb33841b |
13 | 85837aca35 |
14 | 4485a926d9 |
15 | 24d6831c5b |
hex | 14d2aeff57 |
89434029911 has 2 divisors, whose sum is σ = 89434029912. Its totient is φ = 89434029910.
The previous prime is 89434029907. The next prime is 89434029953. The reversal of 89434029911 is 11992043498.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 89434029911 - 22 = 89434029907 is a prime.
It is a super-2 number, since 2×894340299112 (a number of 23 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 89434029911.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (89434029901) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 44717014955 + 44717014956.
It is an arithmetic number, because the mean of its divisors is an integer number (44717014956).
Almost surely, 289434029911 is an apocalyptic number.
89434029911 is a deficient number, since it is larger than the sum of its proper divisors (1).
89434029911 is an equidigital number, since it uses as much as digits as its factorization.
89434029911 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 559872, while the sum is 50.
The spelling of 89434029911 in words is "eighty-nine billion, four hundred thirty-four million, twenty-nine thousand, nine hundred eleven".
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