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90101243340149 is a prime number
BaseRepresentation
bin10100011111001001010100…
…100110100110010101110101
3102211000121001120021211202012
4110133021110212212111311
543302204321243341044
6515343534553454005
724656412542620556
oct2437112446462565
9384017046254665
1090101243340149
11267887a4a270a8
12a132284111305
133b376842875b2
141836ccdd1632d
15a63b17d1359e
hex51f2549a6575

90101243340149 has 2 divisors, whose sum is σ = 90101243340150. Its totient is φ = 90101243340148.

The previous prime is 90101243340131. The next prime is 90101243340217. The reversal of 90101243340149 is 94104334210109.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 88532912911249 + 1568330428900 = 9409193^2 + 1252330^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-90101243340149 is a prime.

It is a super-2 number, since 2×901012433401492 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (90101243340349) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 45050621670074 + 45050621670075.

It is an arithmetic number, because the mean of its divisors is an integer number (45050621670075).

Almost surely, 290101243340149 is an apocalyptic number.

It is an amenable number.

90101243340149 is a deficient number, since it is larger than the sum of its proper divisors (1).

90101243340149 is an equidigital number, since it uses as much as digits as its factorization.

90101243340149 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 93312, while the sum is 41.

The spelling of 90101243340149 in words is "ninety trillion, one hundred one billion, two hundred forty-three million, three hundred forty thousand, one hundred forty-nine".