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90813143294771 is a prime number
BaseRepresentation
bin10100101001100000010101…
…001001011010001100110011
3102220112122121002122120101012
4110221200111021122030303
543400340304140413041
6521050552044301135
725062014230446422
oct2451402511321463
9386478532576335
1090813143294771
1126a32701994837
12a228241b417ab
133b89847c2a9b1
14185d5458352b9
15a773d19783eb
hex52981525a333

90813143294771 has 2 divisors, whose sum is σ = 90813143294772. Its totient is φ = 90813143294770.

The previous prime is 90813143294747. The next prime is 90813143294773. The reversal of 90813143294771 is 17749234131809.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 90813143294771 - 226 = 90813076185907 is a prime.

It is a super-2 number, since 2×908131432947712 (a number of 29 digits) contains 22 as substring.

Together with 90813143294773, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 90813143294771.

It is not a weakly prime, because it can be changed into another prime (90813143294773) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 45406571647385 + 45406571647386.

It is an arithmetic number, because the mean of its divisors is an integer number (45406571647386).

Almost surely, 290813143294771 is an apocalyptic number.

90813143294771 is a deficient number, since it is larger than the sum of its proper divisors (1).

90813143294771 is an equidigital number, since it uses as much as digits as its factorization.

90813143294771 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 9144576, while the sum is 59.

The spelling of 90813143294771 in words is "ninety trillion, eight hundred thirteen billion, one hundred forty-three million, two hundred ninety-four thousand, seven hundred seventy-one".