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913299414689 is a prime number
BaseRepresentation
bin11010100101001001110…
…00110001111010100001
310020022101101222100102202
431102210320301322201
5104430414122232224
61535321452022545
7122661260636204
oct15224470617241
93208341870382
10913299414689
11322367789a02
12129006161a55
136817bbb235c
14322bd81193b
1518b54dc3eae
hexd4a4e31ea1

913299414689 has 2 divisors, whose sum is σ = 913299414690. Its totient is φ = 913299414688.

The previous prime is 913299414673. The next prime is 913299414691. The reversal of 913299414689 is 986414992319.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 627493701025 + 285805713664 = 792145^2 + 534608^2 .

It is a cyclic number.

It is not a de Polignac number, because 913299414689 - 24 = 913299414673 is a prime.

It is a super-3 number, since 3×9132994146893 (a number of 37 digits) contains 333 as substring.

Together with 913299414691, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (913299414619) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 456649707344 + 456649707345.

It is an arithmetic number, because the mean of its divisors is an integer number (456649707345).

Almost surely, 2913299414689 is an apocalyptic number.

It is an amenable number.

913299414689 is a deficient number, since it is larger than the sum of its proper divisors (1).

913299414689 is an equidigital number, since it uses as much as digits as its factorization.

913299414689 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 30233088, while the sum is 65.

The spelling of 913299414689 in words is "nine hundred thirteen billion, two hundred ninety-nine million, four hundred fourteen thousand, six hundred eighty-nine".