Base | Representation |
---|---|
bin | 10100110010110011100011… |
… | …010110101011100010110111 |
3 | 102222210202021002210120002211 |
4 | 110302303203112223202313 |
5 | 43441323211024234431 |
6 | 522300330511314251 |
7 | 25156131131241502 |
oct | 2462634326534267 |
9 | 388722232716084 |
10 | 91452258039991 |
11 | 27159759565352 |
12 | a31008821b987 |
13 | 3c04bac407754 |
14 | 1882454888139 |
15 | a88d3a7152b1 |
hex | 532ce35ab8b7 |
91452258039991 has 2 divisors, whose sum is σ = 91452258039992. Its totient is φ = 91452258039990.
The previous prime is 91452258039971. The next prime is 91452258040009. The reversal of 91452258039991 is 19993085225419.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 91452258039991 - 29 = 91452258039479 is a prime.
It is a super-2 number, since 2×914522580399912 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (91452258039931) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 45726129019995 + 45726129019996.
It is an arithmetic number, because the mean of its divisors is an integer number (45726129019996).
Almost surely, 291452258039991 is an apocalyptic number.
91452258039991 is a deficient number, since it is larger than the sum of its proper divisors (1).
91452258039991 is an equidigital number, since it uses as much as digits as its factorization.
91452258039991 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 62985600, while the sum is 67.
The spelling of 91452258039991 in words is "ninety-one trillion, four hundred fifty-two billion, two hundred fifty-eight million, thirty-nine thousand, nine hundred ninety-one".
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