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91685092190473 is a prime number
BaseRepresentation
bin10100110110001100011001…
…010110011110100100001001
3110000122000020201022220112201
4110312030121112132210021
544004132032100043343
6522555314435240201
725212013024665655
oct2466143126364411
9400560221286481
1091685092190473
112723947a352801
12a349227a49061
133c20b37015122
14188d821567a65
15a8ee164e694d
hex53631959e909

91685092190473 has 2 divisors, whose sum is σ = 91685092190474. Its totient is φ = 91685092190472.

The previous prime is 91685092190431. The next prime is 91685092190557. The reversal of 91685092190473 is 37409129058619.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 80362762262784 + 11322329927689 = 8964528^2 + 3364867^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-91685092190473 is a prime.

It is a super-2 number, since 2×916850921904732 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (91685092190273) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 45842546095236 + 45842546095237.

It is an arithmetic number, because the mean of its divisors is an integer number (45842546095237).

It is a 1-persistent number, because it is pandigital, but 2⋅91685092190473 = 183370184380946 is not.

Almost surely, 291685092190473 is an apocalyptic number.

It is an amenable number.

91685092190473 is a deficient number, since it is larger than the sum of its proper divisors (1).

91685092190473 is an equidigital number, since it uses as much as digits as its factorization.

91685092190473 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 29393280, while the sum is 64.

The spelling of 91685092190473 in words is "ninety-one trillion, six hundred eighty-five billion, ninety-two million, one hundred ninety thousand, four hundred seventy-three".