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925000003 is a prime number
BaseRepresentation
bin110111001000100…
…110000101000011
32101110112212110101
4313020212011003
53343300000003
6231441543231
731631241004
oct6710460503
92343485411
10925000003
11435158214
12219944b17
1311983a8a5
148abc71ab
155631911d
hex37226143

925000003 has 2 divisors, whose sum is σ = 925000004. Its totient is φ = 925000002.

The previous prime is 925000001. The next prime is 925000031. The reversal of 925000003 is 300000529.

It is a weak prime.

It is an emirp because it is prime and its reverse (300000529) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 925000003 - 21 = 925000001 is a prime.

Together with 925000001, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (925000001) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 462500001 + 462500002.

It is an arithmetic number, because the mean of its divisors is an integer number (462500002).

Almost surely, 2925000003 is an apocalyptic number.

925000003 is a deficient number, since it is larger than the sum of its proper divisors (1).

925000003 is an equidigital number, since it uses as much as digits as its factorization.

925000003 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 270, while the sum is 19.

The square root of 925000003 is about 30413.8127008108. The cubic root of 925000003 is about 974.3475812407.

The spelling of 925000003 in words is "nine hundred twenty-five million, three", and thus it is an aban number.