Search a number
-
+
93539125675001 is a prime number
BaseRepresentation
bin10101010001001011000110…
…010110111100001111111001
3110021012020211111102111020002
4111101023012112330033321
544230021112133100001
6530535140415242345
725462656506406626
oct2521130626741771
9407166744374202
1093539125675001
11278937a197a026
12a5a8613b193b5
134026917843786
14191546421534d
15ac3279a8146b
hex5512c65bc3f9

93539125675001 has 2 divisors, whose sum is σ = 93539125675002. Its totient is φ = 93539125675000.

The previous prime is 93539125674979. The next prime is 93539125675003. The reversal of 93539125675001 is 10057652193539.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 93206570466025 + 332555208976 = 9654355^2 + 576676^2 .

It is a cyclic number.

It is not a de Polignac number, because 93539125675001 - 210 = 93539125673977 is a prime.

Together with 93539125675003, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (93539125675003) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 46769562837500 + 46769562837501.

It is an arithmetic number, because the mean of its divisors is an integer number (46769562837501).

Almost surely, 293539125675001 is an apocalyptic number.

It is an amenable number.

93539125675001 is a deficient number, since it is larger than the sum of its proper divisors (1).

93539125675001 is an equidigital number, since it uses as much as digits as its factorization.

93539125675001 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 7654500, while the sum is 56.

The spelling of 93539125675001 in words is "ninety-three trillion, five hundred thirty-nine billion, one hundred twenty-five million, six hundred seventy-five thousand, one".